车流平均行车时间t 一列表格高度太小，求调整\documentclass{ctexart}\begin{document}\begin{table}[!htbp] \caption{评价指标体系}\c...
车流平均行车时间t 一列表格高度太小，求调整
\documentclass{ctexart}
\begin{document}
\begin{table}[!htbp]
\caption{评价指标体系}\centering
\begin{tabular}{c|c}
\Xhline{1.5pt}
\makebox[0.4\textwidth][c]{指标} & \makebox[0.4\textwidth][c]{表达式} \\
\hline
路网密度$\omega$ & $ \omega=\dfrac{ L}{S} $ \\
\hline
\rule{0pt}{15pt} 车流平均行车时间t & $ t=A\cdot t_{0}\left[1+0.5668\left(\dfrac{Q}{C}\right)^{1.4331}\right]+A\cdot\frac{B}{2}\displaystyle\sum_{j=1}^{n}{t_{2}}^{j} $\\
\hline
路网节点度方差E &$ E(\phi)=\dfrac{1}{N}\displaystyle\sum_{m=1}^{N} \left(\phi_{m}-\phi\right)^{2}$ \\
\Xhline{1.5pt}
\end{tabular}
\end{table}
\end{document}
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我还是比较建议这样写：
\documentclass{ctexart} \usepackage{makecell} \begin{document} \begin{table}[!htbp] \caption{评价指标体系} \centering \begin{tabular}{c|c} \Xhline{1.5pt} \makebox[0.4\textwidth][c]{指标} & \makebox[0.4\textwidth][c]{表达式} \\ \hline 路网密度 $ \omega $ & $ \omega=L/S $ \\ \hline \rule{0pt}{15pt} 车流平均行车时间 \( t \) & $ t= A \cdot t_{0} [ 1 + 0.5668 (Q/C) ^{1.4331} ] + A \cdot B/2 \sum_{j=1}^n t_{2}^j $ \\ \hline 路网节点度方差 \( E \) & $ E ( \phi ) = 1/N \sum_{m=1}^N ( \phi_m - \phi )^2 $ \\ \Xhline{1.5pt} \end{tabular} \end{table} \end{document}一周热门 更多>