括号公式内换行报错,缺少\righ.

2019-10-05 11:11发布

这是我写的一小段代码 > \begin{equation} \begin{aligned} \bm{A}_{-k}=\left(&\underbrace{0\quad\cdots\quad 0}_{k...

这是我写的一小段代码 > \begin{equation} \begin{aligned} \bm{A}_{-k}=\left(&\underbrace{0\quad\cdots\quad 0}_{k-1}\quad k(1-\alpha^2)\alpha^k\quad-(k+1)(1-\alpha^2)\alpha^k\quad\underbrace{0\quad\cdots\quad 0}_{N-1}\right. \\ &\left.\alpha^{-k}-\alpha^{k}\quad\alpha^{k+2}-\alpha^{-k}\quad\underbrace{0\quad\cdots\quad 0}_{N-k}\right)^{\rm T} \end{aligned} \label{eqa:8} \end{equation} 总是报错 Extra }, or forgotten \right. \bm{A}_{-k}=\left(& Missing \right. inserted. \bm{A}_{-k}=\left(&
1条回答
poluoren
2019-10-05 11:16
已解决 需将代码改写为如下 > \begin{equation} \begin{aligned} \bm{A}_{-k}=&\left(\underbrace{0\quad\cdots\quad 0}_{k-1}\quad k(1-\alpha^2)\alpha^k\quad-(k+1)(1-\alpha^2)\alpha^k\quad\underbrace{0\quad\cdots\quad 0}_{N-1}\right. \\ &\left.\alpha^{-k}-\alpha^{k}\quad\alpha^{k+2}-\alpha^{-k}\quad\underbrace{0\quad\cdots\quad 0}_{N-k}\right)^{\rm T} \end{aligned} \label{eqa:8} \end{equation} 即分行对齐号必须在左括号左侧,不能被包含进去

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