提问于:
浏览数:
1558
```
\begin{equation}
\begin{cases}
U^{}{gd}=U{gd}+w{g}i{gq}L{1}-(k{p2}k_{p1}(U^{}{dc}-U{dc})+k{p1}k{i1}x{1}-k{p2}i{gd}+k{i2}x{2})\\
U^{*}{gq}=U{gq}-w{g}i{gd}L{1}-(i^{*}{gq}-i{gq})k{p1}-k{i1}x_{2}
\end{cases}
\end{equation}
```
![公式.png](/data/ueditor/php/upload/image/20190912/1568253448765747.png)
1 回答
1
<pre class="brush:plain;toolbar:false">\documentclass{article}
\usepackage{mathtools}
\begin{document}
\begin{equation}
\left\{
\begin{aligned}
U^*_{gd} ={} & U_{gd} + w_g i_{gq} L_1\\
& \bigl( k_{p2} k_{p1} ( U^{*}_{dc} - U_{dc} ) + k_{p1} k_{i1} x_{1} - k_{p2} i_{gd} + k_{i2} x_{2} \bigr)\\
U^*_{gq} ={} & U_{gq} - w_g i_{gd} L_1\\
& -( i^*_{gq} - i_{gq} ) k_{p1} - k_{i1} x_{2}
\end{aligned}
\right.
\end{equation}
\end{document}</pre><p><img src="/data/ueditor/php/upload/image/20190912/1568255509859244.png" title="1568255509859244.png" alt="image.png"></p>
你的回答
请登录后回答
你的回答将会帮助更多人,请务必认真回答问题。