提问于：
浏览数：
2744
这里报错是什么原因呢？
```tex
\documentclass{article}
\usepackage[ruled]{algorithm2e}
\usepackage{graphicx}
\usepackage{amsmath}
\usepackage{graphicx}
\usepackage[utf8]{inputenc}
\begin{document}
\begin{algorithm}%[H]
\caption{The Cascading Bandits on Mobility Management}
\label{alg:CascadeBandits}
%\KwIn{this text}
%\KwOut{how to write algorithm with \LaTeX2e }
Initialization: Observe $\omega_0$, and $\forall e \in E : T_0 (e) = 1, \quad \hat \omega _1 (e)\gets \omega_0(e)$\;
\While{$t \leq T$}{
Compute UCBs $U_t(e)$ for every BSs according to equation \ref{equ:UCB};
//Recommend a list of $L$ BSs from the NCL
Let $a_1^t,a_2^t,\dots,a_L^t$ be $L$ BSs with largest UCBs
$F_t \gets (a_1^t,a_2^t,\dots,a_L^t)$
UE check all BSs on the list and get the feedback $C_t$
//Update statistics
$\forall e \in F $:$T_t(e)\gets T_{t-1}(e)$
\ForAll {$k=1,2,\dots,\min \{C_t,L\}$}{
$e\gets a_k^t$
$T_t(e) \gets T_t(e)+1$
$\hat \omega _{T_{t}(e)}(e)\gets \frac{T_{t-1}(e) \hat \omega_{T_{t-1}(e)}(e)+ \mathds 1{C_t =k}}{T_t(e)}$
$t\gets t+1$
}
}
\end{algorithm}
\end{document}
```
