目标排出如下图所示的效果，第二页的代码从\clearpage那边开始，被我注释掉了...如果直接运行，第一页也跟着错乱了，所以求高人指点一下，第一页的右栏如何平衡➕第二页继续双栏排版？

谢谢了！

归档.zip

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\title{\textbf{\LARGE{数学专业英语期末翻译作业}}} %大括号里填写标题,textbf加粗

\author{\textbf{学院：\underline{应用数学学院}}\\ %\\表示换行

\textbf{班级：\underline{\  \ \, }}\\    %\表示空格,下quad同

\textbf{姓名：\underline{\quad \ \quad \  }}\\

\textbf{学号：\underline{\ \,}}\\ \\

\textbf{翻译页码：P237-238}

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\date{\today} % 自动生成日期

\usepackage{booktabs}%线条粗细

\begin{document}

\par\addtolength{\leftskip}{100pt}

{\small

\noindent This formula is more complicated than it needs to be. If we combine $C=C_{1}-2C_{2}$, and $5C_{3}$ into a single arbitrary constant $C=C_{1}-2C_{2}+5C_{3}$, the formulas simplifies to 

\noindent 这个公式比实际情况还要复杂。如果我们把$C=C_{1}-2C_{2}$,和 $5C_{3}$合并到一个任意常数的式子$C=C_{1}-2C_{2}+5C_{3}$，这个公式可以被简化成

$$ y=\frac{x^3}{3}-x^2+5x+C$$

and $still$ gives all the possible antiderivatives there are. For this reason, we recommend that you go right to the final form even if you elect to integrate term-by-term. Write

\noindent 并且依然给所有可能的不定积分。基于这个原因，我们推荐你直接看最后的形式，即使你需要逐项的整合。写

$$\int(x^2-2x+5)dx=\int x^2dx-\int 2xdx+\int 5dx$$

$$=\frac{x^3}{3}-x^2+5x+C.$$

Find the simpliest antiderivative you can for each part and add the arbitary constant of integration at the end.

\noindent 为每个部分找出它最简形式的反导数，然后在最后取一个任意的正常数。}

$\hfill\color{red}{\blacksquare}$%打小黑格并右对齐

\par

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\noindent\hspace*{-0.3em}\rule[-1pt]{17.85cm}{0.04em}

\hspace*{-0.2em}\colorbox[rgb]{0,0.28,0.56}{\textcolor{white}{\Large{\textbf{EXERCISES}}}} \

\textcolor[rgb]{0.50,0.25,0.25}{\Large{\textbf{4.7}}}

\begin{multicols}{2}

 \noindent{\color[rgb]{0,0.28,0.56}{\footnotesize\textbf{Finding Antiderivatives}}}\\

 {\color[rgb]{0,0.28,0.56}{\footnotesize\textbf{寻找反导数}}}\\

{\scriptsize

In Exercises 1-16, find an antiderivative for each function. Do as many as you can mentally. Check your answer by differentiation.}\\

{\scriptsize 在练习1-16中，为每个函数寻找一个不定积分。在你的能力范围内尽可能寻找。并且通过微分法验证你的答案。

}

\begin{enumerate}[leftmargin=5mm]

 \begin{multicols}{3}

 {\footnotesize

     \item [\bf1.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf2.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf3.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf4.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf5.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf6.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf7.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf8.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf9.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf10.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf11.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf12.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf13.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf14.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf15.]\textbf{a.} {\textbf{$y=2x$}}

   \item [\bf16.]\textbf{a.} {\textbf{$y=2x$}}

   %第二栏

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   \item [\bf b.] {\textbf{$y=2x$}}

   %第三栏

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}

   \item [\bf c.] {\textbf{$y=2x$}}  

  }

 \end{multicols}

\end{enumerate}

%\begin{hlist}3

% \hitem text \hitem text \hitem text

% \hitem text \hitem text \hitem text

% \hitem text \hitem text \hitem text

% \hitem text \hitem text \hitem text

%\end{hlist}

\noindent{\color[rgb]{0,0.28,0.56}{\footnotesize\textbf{Finding Indefinite Integrals}}}\\

{\color[rgb]{0,0.28,0.56}{\footnotesize\textbf{寻找反导数}}}\\

{\scriptsize

In Exercises 17-56, find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation.\\

在练习17-56中，为每个函数寻找一个不定积分。在你的能力范围内尽可能寻找。并且通过微分法验证你的答案。}

\begin{itemize}[leftmargin=4.8mm]

\begin{multicols}{2}

  \item [\bf17.]{\textbf{$\int (sin2x-csc^{2}x)dx$}}

  \item [\bf19.]{\textbf{$\int \frac{1+cos4t}{2}dt$}}

  \item [\bf21.]{\textbf{$\int 3x^{\sqrt{3}}dx$}}

  \item [\bf23.]{\textbf{$\int (1+tan^{2}\theta )d\theta$}}

  \item [\bf25.]{\textbf{$\int cot^{2}xdx$}}

  \item [\bf27.]{\textbf{$\int cos\theta (tan\theta+sec \theta)d\theta$}}

  \item [\bf29.]{\textbf{$\int (2cos2x-3sin3x)dx$}}

  \item [\bf31.]{\textbf{$\int \frac{1-cos6t}{2}dt$}}

  \item [\bf33.]{\textbf{$\int x^{\sqrt{2}-1}dx$}}

  \item [\bf35.]{\textbf{$\int (2=tan^{2}\theta)d\theta$}}

  \item [\bf37.]{\textbf{$\int (1-cot^{2}x)dx$}}

  \item [\bf39.]{\textbf{$\int \frac{csc\theta}{csc\theta -sin\theta}$}}

  \item [\bf41.]{\textbf{$\int (sin2x-csc^{2}x)dx$}}

  \item [\bf43.]{\textbf{$\int (4secxtanx-2(secx)^2{2}dx$}}

  \item [\bf18.]{\textbf{$\int 3x^{\sqrt{3}}dx$}}

  \item [\bf20.]{\textbf{$\int (1+tan^{2}\theta )d\theta$}}

  \item [\bf22.]{\textbf{$\int cot^{2}xdx$}}

  \item [\bf24.]{\textbf{$\int cos\theta (tan\theta+sec \theta)d\theta$}}

  \item [\bf26.]{\textbf{$\int (2cos2x-3sin3x)dx$}}

  \item [\bf28.]{\textbf{$\int \frac{1-cos6t}{2}dt$}}

  \item [\bf30.]{\textbf{$\int x^{\sqrt{2}-1}dx$}}

  \item [\bf32.]{\textbf{$\int (2=tan^{2}\theta)d\theta$}}

  \item [\bf34.]{\textbf{$\int (1-cot^{2}x)dx$}}

  \item [\bf36.]{\textbf{$\int \frac{csc\theta}{csc\theta -sin\theta}$}}

  \item [\bf38.]{\textbf{$\int (1-cot^{2}x)dx$}}

  \item [\bf40.]{\textbf{$\int \frac{csc\theta}{csc\theta -sin\theta}$}}

  \item [\bf42.]{\textbf{$\int \frac{csc\theta}{csc\theta -sin\theta}$}}

\end{multicols}

\end{itemize}

%\clearpage

%\begin{enumerate}[leftmargin=4.8mm]

% \item [\bf44.]\small{\textbf{$\int \frac{1}{2}(csc^{2}x-cscxcotx)dx$}}%上一页自动顺延下来的。

% \begin{multicols}{2}

%  {\balance

%   \item [\bf45.]\small{\textbf{$\int (sin2x-csc^{2}x)dx$}}

%   \item [\bf47.]\small{\textbf{$\int \frac{1+cos4t}{2}dt$}}

%   \item [\bf49.]\small{\textbf{$\int 3x^{\sqrt{3}}dx$}}

%   \item [\bf51.]\small{\textbf{$\int (1+tan^{2}\theta )d\theta$}}

%   \item [\bf53.]\small{\textbf{$\int cot^{2}xdx$}}

%   \item [\bf55.]\small{\textbf{$\int cos\theta (tan\theta+sec \theta)d\theta$}}

%   \item [\bf46.]\small{\textbf{$\int (2cos2x-3sin3x)dx$}}

%   \item [\bf48.]\small{\textbf{$\int \frac{1-cos6t}{2}dt$}}

%   \item [\bf50.]\small{\textbf{$\int x^{\sqrt{2}-1}dx$}}

%   \item [\bf52.]\small{\textbf{$\int (2=tan^{2}\theta)d\theta$}}

%   \item [\bf54.]\small{\textbf{$\int (1-cot^{2}x)dx$}}

%   \item [\bf56.]\small{\textbf{$\int \frac{csc\theta}{csc\theta -sin\theta}$}}

%  }

% \end{multicols}

%\end{enumerate}

\end{multicols}

\end{document}