hlist排版，部分item需要换行排列，如何平衡两栏？

<p></p><p>先说说与你要问的无关的问题：你这个代码没眼看，说实话如果你还是拿用word的方法来写latex，不能做到样式与内容的分离还在手动设置编号、每个标题多带带设置样式的话，我建议你去用word。然后是MWE的问题，你的代码里90%全是与问题无关的代码，请理解最小工作示例的意思。。<br/></p><p><br/></p><p>然后回到你的问题，首先enumerate和enumitem用一个就行了。这里我用的multicol实现的双栏，然后你想要hint对齐，这里你要了解list的距离是怎么排列的，借用enumitem宏包说明文档里面的图</p><p><img src="/data/ueditor/php/upload/image/20200428/1588077627864163.png" style="" title="1588077627864163.png"/></p><p><img src="/data/ueditor/php/upload/image/20200428/1588077627319762.png" style="" title="1588077627319762.png"/></p><p>那么实际上你只需要让\itemindent = \labelwidth + \labelsep，让\leftmargin变成最后计算的距离，最后让编号左对齐就行了。</p><pre class="brush:plain;toolbar:false">\documentclass{article} \usepackage{multicol} \usepackage{enumitem} \usepackage{calc} \begin{document} \setlist{ &nbsp;&nbsp;align=left, &nbsp;&nbsp;labelwidth=.5cm, &nbsp;&nbsp;itemindent&nbsp;=&nbsp;\labelwidth&nbsp;+&nbsp;\labelsep, &nbsp;&nbsp;leftmargin=! } \begin{multicols}{2} \begin{enumerate}[leftmargin=!] &nbsp;&nbsp;\item&nbsp;{\textbf{$\int&nbsp;(1+tan^{2}\theta&nbsp;)d\theta$}}\\ &nbsp;&nbsp;($Hint:&nbsp;1+\tan^{2}\theta&nbsp;=&nbsp;\sec^{2}\theta$) &nbsp;&nbsp;\item&nbsp;{\textbf{$\int&nbsp;\cot^{2}xdx$}}\\ &nbsp;&nbsp;($Hint:&nbsp;1+\cot^{2}x&nbsp;=&nbsp;\csc^{2}x$) &nbsp;&nbsp;\item&nbsp;{\textbf{$\int&nbsp;(1+tan^{2}\theta&nbsp;)d\theta$}}\\ &nbsp;&nbsp;($Hint:&nbsp;1+\tan^{2}\theta&nbsp;=&nbsp;\sec^{2}\theta$) &nbsp;&nbsp;\item&nbsp;{\textbf{$\int&nbsp;\cot^{2}xdx$}}\\ &nbsp;&nbsp;($Hint:&nbsp;1+\cot^{2}x&nbsp;=&nbsp;\csc^{2}x$) \end{enumerate} \end{multicols} \end{document}</pre><p><img src="/data/ueditor/php/upload/image/20200428/1588077803936314.png" title="1588077803936314.png" alt="Screenshot from 2020-04-28 20-42-48.png" style="max-width:650px"/></p>

<p>试试 `... \\ \rlap{Hint: ...}`</p>